-x^2+4x+(-2-x)^2=-1+92-x

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Solution for -x^2+4x+(-2-x)^2=-1+92-x equation:



-x^2+4x+(-2-x)^2=-1+92-x
We move all terms to the left:
-x^2+4x+(-2-x)^2-(-1+92-x)=0
We add all the numbers together, and all the variables
-x^2+4x+(-1x-2)^2-(-1x+91)=0
We add all the numbers together, and all the variables
-1x^2+4x+(-1x-2)^2-(-1x+91)=0
We get rid of parentheses
-1x^2+4x+(-1x-2)^2+1x-91=0
We add all the numbers together, and all the variables
-1x^2+5x+(-1x-2)^2-91=0
We move all terms containing x to the left, all other terms to the right
-1x^2+5x+(-1x-2)^2=91

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